Integral Of (x^2-1)/(x^2+1) - YouTube

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Solve x^2=1 | Microsoft Math Solver

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(*1*)x^2-1=0

(*1*)Subtract 1 from all sides.

(*1*)\left(x-1\right)\left(x+1\right)=0

(*1*)Consider x^2-1. Rewrite x^2-1 as x^2-1^2. The distinction of squares can also be factored the usage of the rule: a^2-b^2=\left(a-b\right)\left(a+b\right).

(*1*)x=1 x=-1

(*1*)To in finding equation solutions, clear up x-1=Zero and x+1=0.

(*1*)x^2-1=0

(*1*)Subtract 1 from either side.

(*1*)x=\frac0±\sqrt0^2-4\left(-1\right)2

(*1*)This equation is in standard shape: ax^2+bx+c=0. Substitute 1 for a, 0 for b, and -1 for c in the quadratic method, \frac-b±\sqrtb^2-4ac2a.

(*1*)x=\frac0±\sqrt-4\left(-1\right)2

(*1*)Square 0.

(*1*)x=\frac0±\sqrt42

(*1*)Multiply -4 occasions -1.

(*1*)x=\frac0±22

(*1*)Take the sq. root of four.

(*1*)x=1

(*1*)Now remedy the equation x=\frac0±22 when ± is plus. Divide 2 via 2.

(*1*)x=-1

(*1*)Now solve the equation x=\frac0±22 when ± is minus. Divide -2 by way of 2.

(*1*)x=1 x=-1

(*1*)The equation is now solved.

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